Monday, August 12, 2019

apply(), lapply(), sapply(), tapply() Function in R with Examples

This tutorial aims at introducing the apply() function collection. The apply() function is the most basic of all collection. We will also learn sapply(), lapply() and tapply(). The apply collection can be viewed as a substitute to the loop
The apply() collection is bundled with r essentialpackage if you install R with Anaconda. The apply() function can be feed with many functions to perform redundant application on a collection of object (data frame, list, vector, etc.). The purpose of apply() is primarily to avoid explicit uses of loop constructs. They can be used for an input list, matrix or array and apply a function. Any function can be passed into apply().
In this tutorial, you will learn

apply() function

We use apply() over a matrice. This function takes 5 arguments:
apply(X, MARGIN, FUN)
Here:
-x: an array or matrix
-MARGIN:  take a value or range between 1 and 2 to define where to apply the function:
-MARGIN=1`: the manipulation is performed on rows
-MARGIN=2`: the manipulation is performed on columns
-MARGIN=c(1,2)` the manipulation is performed on rows and columns
-FUN: tells which function to apply. Built functions like mean, median, sum, min, max and even user-defined functions can be applied>
The simplest example is to sum a matrice over all the columns. The code apply(m1, 2, sum) will apply the sum function to the matrix 5x6 and return the sum of each column accessible in the dataset.
m1 <- matrix(C<-(1:10),nrow=5, ncol=6)
m1
a_m1 <- apply(m1, 2, sum)
a_m1
Output:
Best practice: Store the values before printing it to the console.

lapply() function

lapply(X, FUN)
Arguments:
-X: A vector or an object
-FUN: Function applied to each element of x 
l in lapply() stands for list. The difference between lapply() and apply() lies between the output return. The output of lapply() is a list. lapply() can be used for other objects like data frames and lists.
lapply() function does not need MARGIN.
A very easy example can be to change the string value of a matrix to lower case with tolower function. We construct a matrix with the name of the famous movies. The name is in upper case format.
movies <- c("SPYDERMAN","BATMAN","VERTIGO","CHINATOWN")
movies_lower <-lapply(movies, tolower)
str(movies_lower)
Output:
## List of 4
## $:chr"spyderman"
## $:chr"batman"
## $:chr"vertigo"
## $:chr"chinatown"
We can use unlist() to convert the list into a vector.
movies_lower <-unlist(lapply(movies,tolower))
str(movies_lower)
Output:
##  chr [1:4] "spyderman" "batman" "vertigo" "chinatown"

sapply() function

sapply() function does the same jobs as lapply() function but returns a vector.
sapply(X, FUN)
Arguments:
-X: A vector or an object
-FUN: Function applied to each element of x
We can measure the minimum speed and stopping distances of cars from the cars dataset.
dt <- cars
lmn_cars <- lapply(dt, min)
smn_cars <- sapply(dt, min)
lmn_cars
Output:
## $speed
## [1] 4
## $dist
## [1] 2
smn_cars
Output:
## speed  dist 
##     4     2
lmxcars <- lapply(dt, max)
smxcars <- sapply(dt, max)
lmxcars
Output:
## $speed
## [1] 25
## $dist
## [1] 120
smxcars
Output:
## speed  dist 
##    25   120
We can use a user built-in function into lapply() or sapply(). We create a function named avg to compute the average of the minimum and maximum of the vector.
avg <- function(x) {  
  ( min(x) + max(x) ) / 2}
fcars <- sapply(dt, avg)
fcars
Output
## speed  dist
##  14.5  61.0
sapply() function is more efficient than lapply() in the output returned because sapply() store values direclty into a vector. In the next example, we will see this is not always the case.
We can summarize the difference between apply(), sapply() and `lapply() in the following table:
Function
Arguments
Objective
Input
Output
apply
apply(x, MARGIN, FUN)
Apply a function to the rows or columns or both
Data frame or matrix
vector, list, array
lapply
lapply(X, FUN)
Apply a function to all the elements of the input
List, vector or data frame
list
sapply
sappy(X FUN)
Apply a function to all the elements of the input
List, vector or data frame
vector or matrix

Slice vector

We can use lapply() or sapply() interchangeable to slice a data frame. We create a function, below_average(), that takes a vector of numerical values and returns a vector that only contains the values that are strictly above the average. We compare both results with the identical() function.
below_ave <- function(x) {  
    ave <- mean(x) 
    return(x[x > ave])
}
dt_s<- sapply(dt, below_ave)
dt_l<- lapply(dt, below_ave)
identical(dt_s, dt_l)
Output:
## [1] TRUE

tapply() function

The function tapply() computes a measure (mean, median, min, max, etc..) or a function for each factor variable in a vector.
tapply(X, INDEX, FUN = NULL)
Arguments:
-X: An object, usually a vector
-INDEX: A list containing factor
-FUN: Function applied to each element of x
Part of the job of a data scientist or researchers is to compute summaries of variables. For instance, measure the average or group data based on a characteristic. Most of the data are grouped by ID, city, countries, and so on. Summarizing over group reveals more interesting patterns.
To understand how it works, let's use the iris dataset. This dataset is very famous in the world of machine learning. The purpose of this dataset is to predict the class of each of the three flower species: Sepal, Versicolor, Virginica. The dataset collects information for each species about their length and width.
As a prior work, we can compute the median of the length for each species. tapply() is a quick way to perform this computation.
data(iris)
tapply(iris$Sepal.Width, iris$Species, median)
Output:
##     setosa versicolor  virginica 
##        3.4        2.8        3.0

No comments:

Post a Comment

No String Argument Constructor/Factory Method to Deserialize From String Value

  In this short article, we will cover in-depth the   JsonMappingException: no String-argument constructor/factory method to deserialize fro...